>
> ? A 0.82-ohm, 2w glitch resistor is not good engineering practice. it
> can not possibly limit fault current to a safe value.
Ok, I'm confused. Per the L4-B manual, "In the event of a short circuit,
resistor R-12 [the one we're talking about] ... will be destroyed. The
resistor
protects the diodes in the power supply ...."
So this sounds to me like the intended function of the 0.82 ohm 2W, wire
wound, fire retardent resistor is to fail rapidly -- as in a fuse. It sounds
like
the wire in the resistor is simply there to act as a fusible link, much the
same
way the Buss HV fuse is used in the KWS-1.
Grant
----------------------------
Grant Youngman -- NQ5T
nq5t@home.com
http://www.globeking.com
Double Oak, TX (near Dallas)
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