Oops, I meant to say the transformer secondary current is
three times (2.828) the DC output of the supply in doubler service.
73, Mark WB8JKR
On Wed, 27 Aug 2003 18:27:43 -0400 wb8jkr@juno.com writes:
> Actually in doubler service I think the transformer peak current
> is about four times the DC output current in a capacitor input
> filter.
> A transformer should be designed for doubler service.
>
> 73, Mark WB8JKR
>
>
> On Tue, 26 Aug 2003 11:38:31 -0400 Ron <w8ron@stratos.net> writes:
> > When you feed it to a doubler , the current is not .5 A but .25A.
> >
> > THe remainder may be due to CCS and ICAS duty.
> > ---
> > Ron
> >
> >
> > Mike, K8LH wrote:
> >
> > >Please excuse the dumb question... I'm trying to figure out how
> to
> > >determine the power handling capability of transformers (I did
> take
> > a
> > >quick look through the ARRL Handbook last night)...
> > >
> > >Questions:
> > >
> > >How can you determine the power handling capability of a
> > transformer???
> > >
> > >For example, the secondary on the transformer in my Heath SB-201
> is
> > >rated at 800 VAC at 0.5 amps... I would think this transformer
> > would
> > >only be good for about 400 watts of power (800 x 0.5) but it
> seems
> > that
> > >if you feed this secondary into a full-wave bridge rectifier and
> > >capacitors you would get about 1,000 volts and 0.5 amps under
> load
> > (500
> > >watts), or feed it into a voltage doubler circuit, like that in
> the
> > >SB-201, and you get about 2,000 vdc at 0.5 amps under load (1,000
> > >watts)...
> > >
> > >I'm confused... What am I missing??? Thanks...
> > >_______________________________________________
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> > >Amps@contesting.com
> > >http://lists.contesting.com/mailman/listinfo/amps
> > >
> > >
> > >
> > >
> >
> >
> > _______________________________________________
> > Amps mailing list
> > Amps@contesting.com
> > http://lists.contesting.com/mailman/listinfo/amps
> >
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