Another way to look at feed through power is the drive power causes an rf
voltage to appear between the cathode and ground. This voltage is in series
with the plate voltage and the plate power input is raised by the amount of
the added cathode voltage. The output power will increase along with the
input power.
The tube and circuit has a given plate efficiency and that efficiency
applies to the added cathode voltage. So, it would seem that some of drive
power
would be lost in the process.
73,
Gerald K5GW
In a message dated 8/26/2009 2:09:47 P.M. Central Daylight Time,
ka4inm@tampabay.rr.com writes:
> Grid to Cathode impedance of a tube
> is the grid to cathode voltage divided by the
> grid current!!!
I wouldn't be so quick to say that. Nothing is that simple.
The load on a grounded grid amplifier is seen by the amplifier's driver.
(I assume as long as the GG amplifier is drawing plate current)
A good percentage of the driving power winds up in the grounded grid
amplifier's load.
You drive the cathode, the cathode is connected (through plate
current) to the plate of the tube that is connected through matching
networks etc. to the load.
--
Ron KA4INM
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