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Re: [Amps] gg feedthru power

To: <jtml@vla.com>, <amps@contesting.com>
Subject: Re: [Amps] gg feedthru power
From: "Carl" <km1h@jeremy.mv.com>
Date: Wed, 31 Mar 2010 09:40:32 -0400
List-post: <amps@contesting.com">mailto:amps@contesting.com>
Thats how I remember it also John but its been a long while since I read it!

BTW, when you mentioned the Tyler circuit in that 500KW amp what efficiency 
improvement were you getting?  What class and how is it driven?

Carl
KM1H





----- Original Message ----- 
From: "John Lyles" <jtml@losalamos.com>
To: <amps@contesting.com>
Sent: Tuesday, March 30, 2010 10:25 PM
Subject: [Amps] gg feedthru power


> In Eimac Amateur Service Newsletter AS-33, also in QST in June of 1967, 
> Bill Orr and Bill Sayer (both at Eimac) state this:
> "Strictly speaking, the extra output power is not 'free', as r.f. power is 
> expensive compared to d.c. plate power and may only be
> 'free' if it is unavoidably available. It is generally referred to as 
> feed-through power, but the implication in this term may be
> misleading, as this portion of the drive power does not appear in the load 
> circuit of the cathode-driven stage until after it is converted to a 
> varying
> d.c. plate potential effectively in series with the main amplifier power 
> supply. This converted drive power performs a useful function in class AB2
> and class B linear service by swamping out the undesirable effects of 
> nonlinear grid loading and presenting a reasonably constant load to the 
> exciter."
> (reference is made here to "SSB Principles and Practice", 1964 edition, by 
> Pappenfus, Bruene. and Schoenike)
>
> Its a pretty good explanation of how it works. I think he means that the 
> cathode to grid voltage swing from the driver is in series with the plate 
> to grid voltage swing in the output. Since
> the cathode current and plate current are in the same path, with the 
> slight difference being the grid current, it is essentially an increase in 
> the plate voltage swing, with the same current, so that
> it appears as if the driver power is added to the output power. But there 
> is no mechanism inside of the vacuum tube for RF to flow through and get 
> from the input to the output, besides the
> effect of the electron beam which converts DC into RF at the fundamental 
> frequency.
>
> Fun reading.
> 73
> John
> K5PRO
>
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