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[Amps] L-PI amp network

To: amps@contesting.com
Subject: [Amps] L-PI amp network
From: "jim.thom jim.thom@telus.net" <jim.thom@telus.net>
Date: Sat, 17 Dec 2022 09:55:28 -0800
List-post: <mailto:amps@contesting.com>
Date: Tue, 13 Dec 2022 17:36:44 -0500
From: Steve Bookout <steve@nr4m.com>
To: amps@contesting.com
Subject: [Amps] L-PI amp network


 I cycled all of the unknown tubes thru
this amp.? They all were similar, taking 22 to 27 watts of drive for the
same 1500 watts out;? 550 ma to 600ma @.030 ma grid.

That was the background for my real question for the group.

Based upon GM3SEK's PI/PI-L calculator, I'm working with a plate load
impedance of ~3000 ohms.? I know from my own experience, and that of
others, that it's a pain to get the plate inductor 'right' so that it
all works and tunes, as it should and make power with reasonable
efficiency.

I have never used an L-Pi, but I basically understand the idea.

IS THERE A RECOMMENDED TOOL OUT THERE, WHICH WILL HELP ME FIGURE OUT MY
TWO "L's"?

Using GM3SEK's calculator, I see there is a line, 'Lead inductance
(total from tube to tank, but excluding suppressor)', which I have
played with.? Adding my 'L' inductance there, say '.6uh', does reduce
the inductance associated with PI, and it does raise the value of the C1
capacitor. ? ( I am using a 100 pf /15 KV vacuum variable and right now
as I write this, I don't remember it's minimum C, but it's in the range
of what I think you should see; maybe 5 pf?)? Using this, I was able to
come up with about 15 pf, vs 4 pf in a standard PI configuration.

Suggestions on if this would be an accurate way to figure this out? ?
Or, another/better way? ? And, what should I be looking for as maybe a
ratio of the 'L' vs the 'L' in the PI network. ? As I recall, I think
I'm looking at about 1.7 uh.

I would appreciate any constructive comments, or even precautionary ones.

73 de Steve, NR4M

## Steve, I have been using the GM3SEK spreadsheet for a long time now,
since it 1st came out.  It's what I use to design the L-PI networks.  It
only works on tubes that DON'T require a suppressor.

## assume 1.5 kw out..and a tank eff of 60% on 10m.  1500/.60 = 2.5 kw DC
input.
2500w / 4000vdc =  625 ma required plate current.   (28.6 mhz)

## Use 1.8 for the 'K'.   4000 / (1.8 x .625) =  3555 ohms  plate load Z.
With an overall network Q of 19 , line 39 (input q = 17.2   output q = 1.8)
Enter 0  for all the parasitic lps/rps on lines 46+47.
Enter 10 pf on line 42
Enter 5 pf on line 43
Enter 3 pf on line 53
Enter 50 uh on line 51
Enter 0 on line 48
Enter 0 on line 52

Here's what u get.
C1 = 9.6 pf
L =  1.26 uh
C2 =   198.5 pf

An overall  Q of 19 sucks.   11.825 amps of current through the tank
coil..which is a bunch.
I would use 3/8" OD tubing...or 1/2" to 5/8" wide strap coil.  With tubing
flattened at each end, then enough width to punch a hole big enough for a
1/4-20 brass screw.   DON'T use  SS  hardware.   It will turn black on
you..and ditto with plane jane ferrous steel machine screws.

##  Ok, let's use the L-PI config, which is really a C-L-C-L-C
We will use the tube's anode to grid C (+ strays)  plus the 1st coil, to
form a step down L network..... stepped down low enough, that a normal PI
net can be designed around, with a lot lower loaded q.

Enter .8 uh on line 48.   Lower the overall Q on line 39  to   11.
Ideally, you want this 1st coil to be a little less than the main coil.
Yes, u have to keep juggling with the overall q on line 39, each time u
increment the 1st coil on line 39.   Start with .1 uh..and keep increasing,
while at the same time decreasing the overall q on line 39.

Ok, here is what we get.   Note, the overall network Q on line 39 is = to
the (input Q + output Q).

Overall network Q of 11   (28.6 mhz)

C1 =   12.7 pf     ( input Q of  9.5)
L =   .91 uh
C2 =   171.6 pf.    (output Q of 1.5)

Note the 1st coil's value (.8uh)  is slightly less than the main coil.
Again, use  3/8" tubing or  1/2" to 5/8" wide strap coils for BOTH coils.
Yes, use ur 100 pf vac cap. You won't have any issues, and harmonic
suppression is typ higher when a vac cap is used.  Air caps have the issue
with the rotor wiper contact.  I'm assuming ur vac cap goes down to 5 pf.

Harmonic suppression with the L-PI is superb.  With the lower Q,  you won't
have to constantly be re-tuning  when u qsy.

Jim  VE7RF
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