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[antennaware] discussion with Gary Breed on coax losses

To: <antennaware@contesting.com>
Subject: [antennaware] discussion with Gary Breed on coax losses
From: gary@noblepub.com (Gary Breed)
Date: Thu, 21 Dec 2000 11:35:52 -0500
Billy

Here's the simplest example I could come up with -- 

Case 1. 72 ohm matched system, one feedline.

100 watts is delivered to the line, which has losses that we will 
say are equivalent to 10 ohms of resistance. At the other end, the 
load is 72 ohms. The power delivered to the load is 100 x 72/(72 + 10) 
= 87.8 watts.

Case 2. Parallel 72 ohm lines into a 36 ohm load.

100 watts is delivered to the pair of lines, which now are equivalent
to 5 ohms of resistance. At the other end, the load is 36 ohms.
The power delivered to the load is 100 x 36/(36 + 5) = 87.8 watts.

Clear enough?

73, Gary
K9AY





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