Antennaware
[Top] [All Lists]

[Antennaware] Equivalent Diameter of Triangular Tower

To: antennaware@contesting.com
Subject: [Antennaware] Equivalent Diameter of Triangular Tower
From: Bill Tippett <btippett@alum.mit.edu>
Date: Thu, 26 Feb 2009 09:18:29 -0500
List-post: <antennaware@contesting.com">mailto:antennaware@contesting.com>
I wrote:

 > I've found a reference for the formula I gave and John W1FV
said it originally came from IEEE Transactions on Broadcasting, but
I don't have the exact chapter and verse.  You might ask W1FV.

         After a little more searching:

######################################################
At 11:15 AM 10/19/98 -0700, Eric Gustafson wrote:
 >
 >
 >Does anyone have or know of any single conductor diameter
 >equivalences to use in models of system involving towers?
 >

If you have access to the June 1998 issue of IEEE Transactions on
Broadcasting, check out the article:  "A Method for Modeling Array Elements
When Using NEC and MININEC" by J.L. Smith.  The author discusses methods
for modeling towers and in particular, describes a single-wire
representation for a triangular cross section tower.  His result is that
the radius of the equivalent wire equals the cube root of the quantity
(D*F^2)/2 where D is the diameter of each tower leg and F is the width of
the tower face with all dimensions in the same units.  Some references are
cited to justify this result.

73, John W1FV
#######################################################
http://lists.contesting.com/archives//html/Antennaware/1998-10/msg00018.html

         Interesting that this was published in the same year as
K9AY's reference.  Models and modelers don't always agree but I do
know this one worked very well for me.

                                         73,  Bill  W4ZV



_______________________________________________
Antennaware mailing list
Antennaware@contesting.com
http://lists.contesting.com/mailman/listinfo/antennaware

<Prev in Thread] Current Thread [Next in Thread>