So (1 + 1)/2 = 100%
Makes zero sense since this is really a statistical problem and a simple
average is meaningless - unless of course you just want to make one perfect QSO!
73,
Steve
W1SRD
________________________________
From: VE5ZX <ve5zx@hotmail.com>
To: cq-contest@contesting.com
Sent: Wednesday, April 2, 2014 12:28 PM
Subject: Re: [CQ-Contest] Accuracy Top Ten Box
>An interesting idea. What is the accepted definition for
> calculating "accuracy"?
(% correct calls + % correct exchanges)/2 ?
Syl -VE5ZX
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