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Re: Fw: [TenTec] Capture area (was 80 meter loops)

To: tentec@contesting.com
Subject: Re: Fw: [TenTec] Capture area (was 80 meter loops)
From: Jason Buchanan <jsb@digistar.com>
Reply-to: tentec@contesting.com
Date: Sat, 20 Mar 2004 20:23:29 -0500
List-post: <mailto:tentec@contesting.com>
JAMES HANLON wrote:

Excellent.  Would that same .28 wavelength value carry for all bands or
specific to a single band?

Yes, the same 0.28 wavelength value carries over for all bands. That's a number that I "eye-balled" from figure 18A on page 24 of the book that I recommended to you.

...


From my ARRL Handbook, the length (feet) of a half-wave in space is 492/Freq (mHz) . In words, that's 492 divided by the frequency in megahertz. The book goes on to say that the actual length of a half-wave antenna will be shorter, depending upon the diameter of the wire used and because of the capacitive loading effect of the end insulators. They suggest using Length (feet) = 468/Freq(mHz) for wire antennas at frequencies up to 30 mHz. Remember that is the length for a HALF wavelength. You have to double that to get a full wavelength.

Depending on whether you use 468 or 492 to calculate the length, muliplied by 2, then divided by .28 a 40 meter .28 wavelengths antenna comes out pretty close to 40 feet.



I will have to try this out later this week.



Thanks! jason _______________________________________________ TenTec mailing list TenTec@contesting.com http://lists.contesting.com/mailman/listinfo/tentec

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