Marinus Loewensteijn wrote:
When Coax is terminated at the transmitter end and the far end with an
impedance that is equal to its defined impedance we will have a SWR of 1:1.
Yes.
Only when the currents on inner conductor and on shield are equal and the
current / voltage nodes coincide at the same locations then they'll cancel
radiation.
Yes.
If we have anything else that creates a SWR that is not 1:1 then waves will be reflected from the ends.
Yes.
Hence no longer will the current and voltage nodes be coinciding.
No.
When nodes are no longer coinciding then we will have radiation.
Yes, but they do coincide, even with high SWR.
What is wrong about this, what am I missing here?
Even when there is a high SWR the current nodes in the two conductors
occur the same distance from the (mismatched) load.
You can still get radiation due to unbalanced currents, which may be
caused by non-symmetry of the antenna. Mismatch between the line and
load, and the high SWR it causes, does not by itself cause radiation
from coax.
DE N6KB
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