The formula for the wind area should have said:
"the integral from 0 to Dia of 1/2 surface area of each tube (0.5 x Pi x
Dia), where Dia is the Outside diameter of the tube"
This is because only one side of the tube is exposed to the wind at any
time. I read and re-read my prior posting, sent it, then saw that I left
off the 1/2.
Bill, N3RR
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