Hold on here. Isn't the formula pi*r^2*h=v? My calc says about 78.5 cu ft
or 2.9 cu yds.
Oh, I'm sorry. I just noticed the @stanford.edu.
At 05:18 PM 10/4/03, gdaught6@stanford.edu wrote:
On 4 Oct 2003 at 11:47, David Giuliani wrote:
> I'm installing a concrete base for a Universal Towers MA-550. The
> mfg's dwg calls for a base 2.5' x 2.5' x 5' deep in undisturbed soil,
> using 2.5 cubic yards.
I calculate under 1.25 cubic yards for that hole. You're going to
have a LOT of concrete left over. 3' x 3' x 6' is two yards.
73,
_______________________________________________
See: http://www.mscomputer.com for "Self Supporting Towers", "Wireless
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any questions and ask for Sherman, W2FLA.
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Jim Rhodes K0XU
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_______________________________________________
See: http://www.mscomputer.com for "Self Supporting Towers", "Wireless Weather Stations", and lot's more. Call Toll Free, 1-800-333-9041 with any questions and ask for Sherman, W2FLA.
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