Towertalk
[Top] [All Lists]

Re: [TowerTalk] Near field Far field

To: Steve Hunt <steve@karinya.net>
Subject: Re: [TowerTalk] Near field Far field
From: Bob Nielsen <n7xy@clearwire.net>
Date: Sun, 21 Sep 2008 13:34:08 -0700
List-post: <towertalk@contesting.com">mailto:towertalk@contesting.com>
That is the generally-used formula.  As you said it isn't an abrupt  
transition, but the point where the 1/r^2 and 1/r^3 terms in the  
field strength equations become small enough to be ignored.  The  
relevant math can be found in "Antennas" by Kraus (W8JK).

73,
Bob, N7XY

On Sep 21, 2008, at 10:50 AM, Steve Hunt wrote:

> When I'm making Far Field measurements on an HF antenna - for example
> plotting its azimuth pattern by rotating it whilst measuring relative
> field strength at a remote point - how far away do I need to be to
> ensure I'm in the Far Field?
>
> Clearly there isn't an abrupt transition from Near Field to far Field,
> but some references seem to quote [2* D*D/Wavelength] as a transition
> point, where D is the maximum dimension of the antenna. So, for a  
> point
> source the answer is zero, which sounds right. But for a 20m half-wave
> dipole the answer would be about 32ft which sounds a bit close in.  
> For a
> mini-beam such as the MA5B the prediction would be even closer -  
> about 9ft.
>
> Does this sound right? If not, what is the right formula?
>
> 73,
> Steve G3TXQ
>
> _______________________________________________
>
>
>
> _______________________________________________
> TowerTalk mailing list
> TowerTalk@contesting.com
> http://lists.contesting.com/mailman/listinfo/towertalk

_______________________________________________



_______________________________________________
TowerTalk mailing list
TowerTalk@contesting.com
http://lists.contesting.com/mailman/listinfo/towertalk

<Prev in Thread] Current Thread [Next in Thread>