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Re: [TowerTalk] Elevated vertical

To: 'Paul Christensen' <w9ac@arrl.net>, "towertalk@contesting.com" <towertalk@contesting.com>
Subject: Re: [TowerTalk] Elevated vertical
From: Al Kozakiewicz <akozak@hourglass.com>
Date: Sat, 24 Dec 2011 12:35:47 -0500
List-post: <towertalk@contesting.com">mailto:towertalk@contesting.com>
Sigh...  This wasn't meant to be an exercise in ignoring the context!

I'm talking about a single feedline with a uniform characteristic impedence and 
resonable loss, with reasonable defined as a level that does not significantly 
attenuate the reflected wave.  I fully realize that I've now left the term 
"significantly" just dangling out there waiting to picked apart!

With respect to the context busting scenario described below:  If I correctly 
understand the setup, the answers are D and 50 ohms.

Merry Christmas to all!

Al
AB2ZY


-----Original Message-----
From: Paul Christensen [mailto:w9ac@arrl.net] 
Sent: Saturday, December 24, 2011 10:38 AM
To: Al Kozakiewicz; towertalk@contesting.com
Subject: Re: [TowerTalk] Elevated vertical

> "Adding a matching circuit at the transmitter (tuner) or adjusting the 
> length of the feedline such that a 50 ohm resistive impedence is 
> presented to the source does not change the VSWR in the feedline.  
> Yes, the VSWR between the source and the tuner will be 1:1, but the 
> VSWR in the feedline will remain unchanged."

Sometimes VSWR does change significantly along a line -- and not always for 
reasons of loss nor common-mode RF current on the outside of a coaxial line. 
Consider this example:

At the operating frequency, a dipole at its input terminals is exactly 50 ohms 
resistive (50+j0).  Let's feed the dipole with an electrical half-wave of 
low-loss 600-ohm open line. VSWR on the line is 12:1.  Correct? 
Finally, let's connect a random length of 50 ohm, low-loss coax to the input of 
the 600 ohm line.

What is the VSWR on the 50 ohm section of line?

Possible Answers:

A. Is it still about 12:1 because VSWR does not change on a low-loss line.
B. Not enough information because you didn't state the coax length.
C  It's now about 6:1
D. It is now 1:1
E. You can't terminate a coaxial line into a 600-ohm balanced line without a 
current balun and get an answer.
F. None of the above.

Bonus question:  What is the impedance at the input to the 600-ohm line section?

So, here we have one transmission line composed of two types.  Ignoring loss, 
is the VSWR really the same at all points on the transmission line?

Paul, W9AC

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