Thanks guys!
This was clearly too obvious. Now I feel really stupid!!!
( AD5GB dons the pointy hat..... steps away from the amplifier )
--
Microsoft is NOT the answer
Microsoft is the question and the answer is NO!
Proud to be 100% Microsoft Free
--- On Fri 11/22, Gary Schafer wrote:
From: Gary Schafer [mailto: garyschafer@attbi.com]
To: ad5gb@myway.com
Cc: stevek@jmr.com, amps@contesting.com
To: <amps@contesting.com>
Date: Fri, 22 Nov 2002 11:42:22 -0500
Subject: Re: [Amps] Passive grid: How to calculate..... ?
> The math looks right to me. If your going to run the tubes in AB1 then
> whatever the bias voltage is set at is the maximum peak voltage that you
> need.
> Any more and you will drive the tubes into grid current.
>
> 73
> Gary K4FMX
>
>
> ad5gb wrote:
>
> > Maybe I have the math wrong....
> >
> > E=sqrt(P*R)
> >
> > so
> >
> > P == 100
> > R == 50
> >
> > then E = 70.7106 or approx 100V Peak
> >
> > Or am I wayyyyyyyyyyyyyy off?
> >
> > --
> > Microsoft is NOT the answer
> > Microsoft is the question and the answer is NO!
> >
> > Proud to be 100% Microsoft Free
> >
> > --- On Fri 11/22, Steve Katz wrote:
> > From: Steve Katz [mailto: stevek@jmr.com]
> > To: ad5gb@myway.com, amps@contesting.com
To: <amps@contesting.com>
> > Date: Fri, 22 Nov 2002 07:56:44 -0800
> > Subject: RE: [Amps] Passive grid: How to calculate..... ?
> >
> > >
> > >
> > > > I'm also assuming 100V pk for a 100W transciever. (
> someone please
> > > > correct me if I'm way out in orbit somewhere!!! )
> > > >
> > > [Steve Katz] Where'd the 100V come from? E = SQRT P*R.
> -WB2WIK/6
> > >
> > > > Many thanks!
> > > >
> > > >
> > > > --
> > > > Microsoft is NOT the answer
> > > > Microsoft is the question and the answer is NO!
> > > >
> > > > Proud to be 100% Microsoft Free
> > > >
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> > > > _______________________________________________
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> > > > http://lists.contesting.com/mailman/listinfo/amps
> > >
> >
> > _______________________________________________
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> >
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