To: | <towertalk@contesting.com> |
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Subject: | [Towertalk] Wind force calculations |
From: | n6tqs@arrl.net (n6tqs@arrl.net) |
Date: | Wed, 18 Dec 2002 13:23:41 -0500 (EST) |
Thanks to those who answered my question. The simplistic answer is that the approximate force in pounds per square foot is .004 (or maybe .0025) times the square of the wind speed in miles per hour. That's good enough for me. The K7NV site has lots of good information, and thanks for the pointer there. 73, doug |
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