Gary,
The wind load of the element starting with 6 feet of 3/4 inch and then 66
inches each of 5/8, 1/2 and 3/8 is 2.55 SF. The weight is 4.9 pounds not
counting hardware. It is rated for 41 mph.
This doesn't answer the question about what it will take to turn it over but
first you probably want the elements to be rated for higher than 41 mph. If
you want me to tell you what you can do to make them stronger, specify the wind
rating for the element and I'll tell you.
I did something similar to what you described for a very heavy duty full sized
40 meter vertical on the beach - starting with 2 inch X 1/8 inch wall at
bottom. I used a section of PVC electrical conduit (2 inch schedule 40) and
drilled 3/4 inch holes at right angles and about an inch or two apart. I then
used aluminum tubing to create a "+" at the bottom that extended out about six
feet in all four directions. A big rock on each end made it very stable.
I would think a sack of pre mixed concrete either formed up or not at each
vertical location would also be easy to accomplish and do the job.
73... Stan, K5GO
> On Aug 30, 2016, at 1:20 PM, Gary Smith <Gary@ka1j.com> wrote:
>
> I'm having to play games with setting up eight, short, active
> vertical elements on an incredibly rocky area. I am not able to drive
> in ground rods, much less the base of the antennas. I'm coming up
> with a plan to make wooden bases for them and hold them down with
> rocks.
>
> Since I live on the ocean's edge and have to contend with hurricane
> force winds every so often, I'm trying to figure out the wind loading
> of the verticals I'm considering. I'll buy the aluminum sections from
> DXE and prefer to use larger sections just because of branches
> falling at the marsh edge, as they always do. But thicker pieces will
> have more wind loading and that is a problem.
>
> If I use the thinnest configuration I'll have about 22 feet tall made
> of .375, .5, .625 & .750 sections.
>
> I asked what the wind loading would be and nobody I talked to was
> able to give me a clue. Does anyone know a formula to figure the wind
> loading of tapered elements?
>
> Thanks & 73,
>
> Gary
> KA1J
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