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Re: [TowerTalk] Polarity question..on a dipole

To: towertalk@contesting.com
Subject: Re: [TowerTalk] Polarity question..on a dipole
From: Patrick Greenlee <patrick_g@windstream.net>
Date: Fri, 31 Mar 2017 21:25:09 -0500
List-post: <towertalk@contesting.com">mailto:towertalk@contesting.com>
Farm and Ranch stores like Orchelns, Atwoods, Tractor Supply, etc sell insulating tubing (plastic, don't know composition) for use with electric fencing. It is 1/4 inch or maybe a tad less. My fence charger is rated for over 200 miles of fence with a fairly high joule rating and puts my digital meter (good for up to 10,000 Volts) into over scale , i.e. has more output than 10KV. I can have a wire insulated with this tubing against grounded pipes or buried in conductive soil and not get arcing to the pipe or the damp conductive dirt.

This stuff might just help stop an antenna from arcing to any part of a tree. I haven't tried it with antennas as I have no need for that but have used a lot of lot for underground distribution of the hot wire.

Patrick        NJ5G


On 3/31/2017 3:39 PM, jimlux wrote:
On 3/31/17 12:25 PM, Jim Thomson wrote:
Ok, the peak V on the tips of a dipole is sky high. But what about the polarity between the ends ? If one end is + 10 kv, is the other end at – 10 kv ?? Is there a 20 kv
potential difference between them at all times ?


It's very hard to calculate (or measure) the actual voltage at the ends - best you can say is "it's high". You can infer a voltage by calculating the feedpoint impedance of a 1 wavelength long doublet, then putting in 2x power (each half radiates full power), and using Ohms law.


Yes, it would be opposite polarity. but not "at all times" because it goes through zero every half cycle.



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