SV: SV: [AMPS] Final..
George T. Daughters
gdaught6@leland.Stanford.EDU
Tue, 4 Jan 2000 09:19:09 +0008
Rich wrote...
> > I do not agree. In AB1, the grid looks like a capacitor.
> >
To which John replied...
> Now you got me!!!!! How the hell can one develop power into a pure reactance?????
> Surely the grid of a tube biased for AB1 is resistive?
My understanding is that one DOES NOT deliver power to the grid of an
AB1 amplifier. The driving voltage is always such that the grid
is never driven into the region where grid current flows. All one
does is charge and discharge the "input capacitance" of the tube.
If one refers to one of the ARRL handbooks, in the tube
charactersitics section, one finds "driving power = 0".
So the grid of a tube biased for AB1 is NOT resistive. A good way to
make the input of such an amplifier appear as a constant resistive
load to the exciter (a good thing!) is to put a fixed non-inductive
resistor from the grid to (RF) ground. The resistor dissipates
(wastes!) the drive power. Another benefit of such a resistor is
that it enhances the stability of the amplifier.
73,
George T. Daughters, K6GT
--
FAQ on WWW: http://www.contesting.com/ampsfaq.html
Submissions: amps@contesting.com
Administrative requests: amps-REQUEST@contesting.com
Problems: owner-amps@contesting.com
Search: http://www.contesting.com/km9p/search.htm