[AMPS] Power Handling of Resistors

[measures]

>
>Please stop the personal attacks!
>Thank you.
>Will,  K6NDV
>AMPS reflector
>
I agree with Will on this matter.  Playing the Anal Retentive/Expulsive 
Card is clearly over the top, Dave - - unless it's 
alt.religion.scientology. .  //  Will -- how about putting "anal" on the 
official AMPS banned word list, along with the n-word?  

later

>-----Original Message-----
>From: owner-amps@contesting.com [mailto:owner-amps@contesting.com]On
>Behalf Of Wt8r@aol.com
>Sent: Wednesday, March 08, 2000 6:04 AM
>To: jono@enteract.com; amps@contesting.com
>Subject: Re: [AMPS] Power Handling of Resistors
>
>
>
>In a message dated 3/7/00 11:22:45 PM Eastern Standard Time,
>jono@enteract.com writes:
>
>>
>>  The amount of energy stored in the capacitor banks of a power supply that
>>  has a voltage of 4000 Volts and 32 uF of capacitance is:
>>
>>  J = (C*E^2)/2            source: Radio Handbook by Bill Orr 23rd ed. pg
>2-7
>>
>>  C is capacitance in Farads and E is voltage.
>>
>>  So using plugging values of C = 32E-6, and E = 4000 into my handy-dandy
>Boy
>>  Scout calculator, we get the following:
>>
>>  J = (32E-6 * 16,000,000)/2
>>  J = 512/2
>>
>>  J = 256 Joules!
>>
>>  So let's see:
>>
>>  We've established the fact that 320 Joules into my resistor network will
>not
>>  damage the resistors.
>>
>>  Yet 256 Joules will destroy a tank circuit according to what you say.
>>
>>  Glad I don't live in your universe.
>>
>>  73,
>>
>>  Jon
>>  KE9NA
>>
>----------------------------------------------------------------------------
>--
>-------------------------------
>
>Anyone who has ever seen the results of such an arc discharge as I have
>described knows the Dr. Jon is ANAL RETENTIVE.
>
>This is enuf time wasted on this foolishness.
>
>Dave in Dayton, WT8R
>
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>


-  Rich..., 805.386.3734, www.vcnet.com/measures.  
end


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