[AMPS] basic question about dipping the plate

[measures]

>
>Rich,
>
>I believe that is only true if there is no load connected across the shunt 
>side of the L-network. 
>In that case the L-network simply becomes a hi-q series resonant trap to 
>ground (e.g. a near
>dead short). Connect a finite resistive load across the shunt element and 
>that is no longer true.

€  Try proving this with a dipmeter, Mike.   

>Under this condition, the currents through the inductor and capacitor are 
>no longer equal. Thus 
>their respective voltage drops are no longer in anti-phase (e.g. no more 
>dead short).
>
>73 de Mike, W4EF.....................
>
>> ?  Murphy said that things are more complicated than they look.  A 
>> pi-network is two L-networks in series.  At resonance, an L-network is a 
>> dead short.  Thus, L-networks are not oprated at resonance.  When my 
>> SB-220 is tuned for max output on 3820KHz, a dipmeter shows that the tank 
>> resonates several hundred KHz lower.  Pi-networks are not like parallel 
>> resonant tanks in days of yore.  
>> 
>> cheers, Jeff

-  Rich..., 805.386.3734, www.vcnet.com/measures.  
end


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