[AMPS] Finding the Q of a Coil

[Bill Smith]

Hung up trying to calculate the Q of a coil I want to
build.  It will be 2 inches in diameter with 26 turns
of #10 wire.  The length is 5.3 inches.  4.9 Turns per
inch.  HAMCALC computes this at 11uh of inductance.


If I got it right
Inductive Reactance of this coil on 10 meters=
2*3.14*29000000*.000011 or 2003 ohms

Q of this coil should be the Inductive Reactance
divided by the internal resistance of the coil's wire
(factoring in the RF).  This is where I got bogged
down.  Couldn't come up with an appropiate number.
Where am I going wrong?
73,
Bill

=====
Bill Smith KO4NR

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