[Amps] RMS-PEP & 2x8877

[Steve Thompson]

----- Original Message -----
From: Martin, Maximo <Maximo.Martin@icm.siemens.com>
To: 'Bill Fuqua' <wlfuqu00@uky.edu>; <amps@contesting.com>
Sent: 07 November 2002 15:31
Subject: RE: [Amps] RMS-PEP & 2x8877


> If,
> RMS voltage times RMS current (both in phase) is the equal to AVERAGE
> and PEP is AVERAGE too, so
> PEP=RMS voltage times RMS current?
Yes - you do the calculation with the *rf* rms voltage and current at the
peak of the modulation envelope.

Steve