[Amps] Measuring RF Power
David Kirkby
david.kirkby at onetel.net
Fri Mar 25 21:12:50 EST 2005
R. Measures wrote:
>>>
>>> The right answer is that RMS current x RMS potential = AC P
>>
>>
>> Any chance of you substantiating what you have said?
>
>
> Does P = I x E?
Rich,
I asked you to substantiate why you said K4FMX was wrong when he said
you can not find RMS power by multiplying RMS voltage by RMS current.
That should not need me to answer a question.
You have in the past gone to great lengths to try to back up your views
on parasitic oscillations - is it asking too much to ask you to
substantiate something as simple as power in a resistor?
I think Gary is right, and you are wrong, and I have rigorously proved
that.
In any case, it would be pointless for me to try to answer your question
when nothing is not defined properly.
--
Dr. David Kirkby,
G8WRB
Please check out http://www.g8wrb.org/
of if you live in Essex http://www.southminster-branch-line.org.uk/
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