[Amps] Measuring RF Power

[R.Measures]

On Mar 25, 2005, at 6:12 PM, David Kirkby wrote:

> R. Measures wrote:
>
>>>>
>>>> The right answer is that RMS current x RMS potential = AC P
>>>
>>>
>>> Any chance of you substantiating what you have said?
>>
>>
>> Does P = I x E?
>
> Rich,
>
> I asked you to substantiate why you said K4FMX was wrong when he said
> you can not find RMS power by multiplying RMS voltage by RMS current.
> That should not need me to answer a question.
>
> You have in the past gone to great lengths to try to back up your views
> on parasitic oscillations - is it asking too much to ask you to
> substantiate something as simple as power in a resistor?
>
> I think Gary is right, and you are wrong, and I have rigorously proved
> that.
>
> In any case, it would be pointless for me to try to answer your 
> question
> when nothing  is not defined properly.

What does "nothing is not defined properly" mean?   As I understand 
this matter, for AC, V-peak ^2 / R = P-peak, V-rms^2 / R = P-rms.  If 
the last equation is true, then P-rms = V-rms x I-rms.
>
> -- 
> Dr. David Kirkby,
> G8WRB
>
> Please check out http://www.g8wrb.org/
> of if you live in Essex http://www.southminster-branch-line.org.uk/
>
>
>
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>

Richard L. Measures, AG6K, 805.386.3734.  www.somis.org