[Amps] Measuring RF Power

[Steve Thompson]

R. Measures wrote:
> On Mar 26, 2005, at 3:05 AM, Steve Thompson wrote:
>
>> R. Measures wrote:
>>> On Mar 26, 2005, at 1:10 AM, Steve Thompson wrote:
>>>
>>>> R.Measures wrote:
>>>>> What does "nothing is not defined properly" mean?   As I
>>>>> understand this matter, for AC, V-peak ^2 / R = P-peak, V-rms^2 /
>>>>> R = P-rms. If the last equation is true, then P-rms = V-rms x
>>>>> I-rms.
>>>>
>>>> It isn't true. V-rms^2/R = Pmean (or average).
>>>>
>>> So what does one find by multiplying V-rms by I-rms?
>> Pmean (or average).
>
> Is that not the heat produced in the R a.k.a. P-rms ?
As David said, yes it's the power, no it's not the rms power.

Vrms is the (square)Root of the Mean of the Squares (of the Voltage
samples). When you work out Vrms^2 in order to work out the power, you are
squaring the squareroot, so the r in rms disappears and you are left with
the Mean of the Squares (of the Voltage samples) --- (V^2)mean or
(V^2)average, if you prefer. (V^2)average/R = Paverage.

Steve