[Amps] grid resonance

Bill Turner dezrat at copper.net
Sun Aug 6 12:57:16 EDT 2006


ORIGINAL MESSAGE:

On Sat,  5 Aug 2006 14:23:26 +0200 (CEST), you wrote:


>Actually, the GDO won't measure a parallel resonant circuit!
>Just consider what happens. We'll put a coil in parallel with a capacitor, and couple (magnetically) the GDO to the coil. The magnetic field from the GDO coil induces a current in each turn of the coil to which it is coupled. The current induced is in series with the coil, and so the circuit is really a series resonant circuit, not a parallel one. The same thing happens with link coupling to a parallel L and C.

------------ REPLY SEPARATOR ------------

I can't believe you would say such a thing, Peter. Perhaps I missed
the smiley face? :-)

You are confusing the current within a component with the current
within a circuit. 

Bill, W6WRT


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