[Amps] tube impedance, figuring tank circuit values

[TexasRF at aol.com]

We are trying to match 50 ohms to the tube plate under full power output  
conditions for the class of operation. Full power output happens with full  
drive, maximum plate current and whatever plate voltage is present under these  
conditions. Therefore, the voltage to be used is the full load value which is  
invariably less than no load conditions due to power supply and ac line voltage  
IR drop.
 
73,
Gerald K5GW
 
 
 In a message dated 3/31/2006 10:22:21 A.M. Central Standard Time,  
gpatterson53 at hotmail.com writes:

ok....  one guy says use the "open circuit voltage" the other guy say use the 
 
loaded "operating voltage" ..................who is  correct


>From: "Phil Clements"  <philc at texascellnet.com>
>To: "'Partain, Chuck'"  <Chuck_Partain at maxtor.com>,<amps at contesting.com>
>Subject:  Re: [Amps] tube impedance, figuring tank circuit values
>Date: Thu, 30  Mar 2006 16:20:27 -0600
>
>
> >
> > So, when I  power up my amp, I see 3910vdc on my plate. The way I have it
> >  configured, I put 330vdc on the screen grid
> > and -130volts on the  control grid., when I bring the control grid to 
>-69v,
> > the  tube pulls current. The voltage on the plate is
> > dropping to ~3600  to 3700. Is this the value I would use to figure the
> > impedance of  the tube for tank calculations?
>
>
>No, the voltage and  current of the amp when it is running at what you plan
>to operate it at  are the values that you plug into the formula. Say that  
>the
>voltage drops to 3500 volts at an operating anode current  of 1 amp; your
>tank should be configured for that, not the resting  anode I.
>
>(((73)))
>Phil,  K5PC
>
>
>
>_______________________________________________
>Amps  mailing  list
>Amps at contesting.com
>http://lists.contesting.com/mailman/listinfo/amps


_______________________________________________
Amps  mailing  list
Amps at contesting.com
http://lists.contesting.com/mailman/listinfo/amps