[Amps] AM On a linear

[Bill L. Fuqua]

I think you are referring to grid driven class C. But there the power supplied the grid is limited by the driver and none in going to the output. When grounded grid and normal B+ is applied most of the power goes to the output and some to the grid. If the plate voltage goes to zero just about all the available power goes to the grid and a little possibly to the output. 

73
Bill wa4lav


-----Original Message-----
From: "Gary Schafer" <garyschafer at comcast.net>
To: <wlfuqu00 at uky.edu>, <edk0kl at centurytel.net>
Date: Wed, 8 Nov 2006 20:50:00 -0600
Subject: RE: [Amps] AM On a linear

But if the amp is driven into class C as it would need to be in order to
plate modulate it wouldn't the same thing exist most of the time that the
tube was in cutoff?

73
Gary  K4FMX

> -----Original Message-----
> From: amps-bounces at contesting.com [mailto:amps-bounces at contesting.com] On
> Behalf Of Bill L. Fuqua
> Sent: Wednesday, November 08, 2006 8:17 PM
> To: edk0kl at centurytel.net
> Cc: amps at contesting.com
> Subject: Re: [Amps] AM On a linear
> 
> All of you are overlooking the fact that during the negative swing of the
> modulator when the plate voltage is near zero  just about all the power
> will actually go to the grid. The same reason why you should not drive the
> tube with out the B+ on. You will possibly fry the grid if you don't
> modulate the driver too.
> 
> 73
> Bill wa4lav
> 
> -----Original Message-----
> From: "Edwin Karl" <edk0kl at centurytel.net>
> To: <amps at contesting.com>
> Date: Wed, 8 Nov 2006 19:31:58 -0600
> Subject: [Amps] AM On a linear
> 
> We are overlloking the feed through RF from the grounded grid
> configuration.
>  A portion of the driving RF will always appear in the output, thus you
> can never "pinch off" the carrier and get 100% modulation.
> 
> ed K0KL
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