[Amps] Class A for AM

Gary Schafer garyschafer at comcast.net
Tue Nov 14 23:26:36 EST 2006


No. Push pull has nothing to do with amplitude linearity in RF service.

73
Gary  K4FMX

> -----Original Message-----
> From: amps-bounces at contesting.com [mailto:amps-bounces at contesting.com] On
> Behalf Of Robert B. Bonner
> Sent: Tuesday, November 14, 2006 8:16 PM
> To: 'Tom W8JI'; 'Gary Schafer'; 'KA5MIR'; amps at contesting.com
> Subject: Re: [Amps] Class A for AM
> 
> Hey Tom, isn't that why they went to PUSH PULL finals with a link coupled
> output?  Still simulates class A with a pair of class B finals...
> 
> I think a couple nice 4-1000's glowing in the rack should just about do
> it.
> 
> Modulate it anyway you'd like.  Sometimes just sometimes the old way is
> the
> best way.
> 
> I wonder if I could still build a link coupled final?  The last time I did
> one was my second novice transmitter a little 6DQ6 25 watter.
> 
> 4-1000's? Whoops the only things I have pairs of here are:  3-500's 8877's
> 3CX3000's and YC-156's drat fresh outta 4-1000's..  Oh and you guys had me
> all excited there for a minute.
> 
> BOB DD
> 
> -----Original Message-----
> From: amps-bounces at contesting.com [mailto:amps-bounces at contesting.com] On
> Behalf Of Tom W8JI
> Sent: Tuesday, November 14, 2006 8:06 PM
> To: Gary Schafer; 'KA5MIR'; amps at contesting.com
> Subject: Re: [Amps] Class A for AM
> 
> > Except in class A the input power never changes. If it is
> > set up for 6000
> > watts input in order to provide 1500 watts output @25%
> > efficiency then the
> > input power will always be a constant 6000 watts with or
> > without modulation
> > or carrier.
> >
> > When it is putting out 375 watts carrier the input power
> > will still be 6000
> > watts.
> >
> > So the dissipation would be 6000 watts minus power out for
> > any given output
> > power.
> 
> 
> That's the way I see it also.
> 
> Since it should make around 50% on peaks it should make
> around 25% on carrier, and 3000 watts plus headroom of
> standing power should do it.
> It will just be useful output power minus standing zero
> signal dissipation.
> 
> 73 Tom
> 
> 
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