[Amps] winding an HV transformer

[Paul Decker]

I've been holding this question for a couple of days now, I'm sure it is very simple and perhaps I just need some reassurance on the answer. 



If you have been following some of this smps discussion, I've got 100Khz pulsed DC (0 - 340v) which is generated by directly rectifing and filtering the 240 V AC mains and providing that into an h-bridge.   The h-bridge dumps the 340 V 100Khz square wave into the transformer. 



As the QST article recomends, I've wound the transformer with five turns on the primary and had calculated that I need 30 turns on the secondary.   Performing some small signal tests, inputting 3.4v pk-pk square wave from my signal generator yeilds about 20.4 volts pk-pk square wave.   I believe this relationship should be linear and inputting 340 V will yeild 2040 volts on the secondary.    



At this point the secondary dumps into a full wave bridge rectifier followed by a filter capacitor.   This is where I am unclear.    When I rectify this with the full wave bridge, will I get 2040 * 0.90 or will I get  2040 * 1.414 as the final DC output?     Part of me says I get the 1.414 value of 2885 VDC, however reading through the handbook, I seem to be reading I'll get 0.90 the output voltage. 



thanks, 

Paul