[Amps] Calculation of Tube Impedance

[Lee Buller]

I think it is Plate V divided by (Plate I times the "K" factor) or

Resistance Anode = V/(I x 1.8)  some people use 1.87

Lee
K0WA



________________________________
From: "TexasRF at aol.com" <TexasRF at aol.com>
To: df3kv at t-online.de; petervandaalen at kpnmail.nl; amps at contesting.com
Sent: Sat, May 1, 2010 12:06:44 PM
Subject: Re: [Amps] Calculation of Tube Impedance

While it is the plate voltage swing that generates the rf power, it is  
customarily accepted that the k factor takes care of that issue. Plate V times  
plate I divided by k factor gives the complete answer.

In actual practice, either method gets you close enough with the  
consequence of a slightly different loaded Q between the two methods.

73,
Gerald K5GW





In a message dated 5/1/2010 10:45:48 A.M. Central Daylight Time,  
df3kv at t-online.de writes:

Peter,  you are right

73
Peter

-----Original Message-----
From:  amps-bounces at contesting.com [mailto:amps-bounces at contesting.com] On
Behalf  Of Peter van Daalen

Isn't it the anode voltage swing instead of the  anode voltage ?
Pse discard if I'm wrong.

73,
Peter,  PE1E

----- Original Message ----- 
From: "Phil Clements"  <philc at texascellnet.com>
To: "'Lee Buller'" <k0wa at swbell.net>;  <amps at contesting.com>
Sent: Thursday, April 29, 2010 9:57  PM
Subject: Re: [Amps] Calculation of Tube Impedance

snip...(Peter  )

In the case of a tube running
> AB2, (grounded grid) with an  anode voltage of 4000 volts, and a current 
of

> 1
> amp, the  output impedance would be 2222 ohms. (E divided by the sum of 1 
X
> 1.8)  The 1.8 is the K factor for the class of operation.
>
>  (((73)))
> Phil, K5PC
>
>
>
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> Amps mailing  list
> Amps at contesting.com
>  http://lists.contesting.com/mailman/listinfo/amps  

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