[Amps] Conventional" current flow

Jim Garland 4cx250b at miamioh.edu
Fri Dec 2 23:12:11 EST 2016


Good question, Dick. The large potential difference between the anode
(plate) and cathode results in a strong electric field inside the tube. The
lines of electric field start at the plate and end on the cathode. The
electric field exerts an attractive force on the negatively charged
electrons, which basically sucks them into the anode. At any point in the
space inside the tube the force F obeys the equation F = -e E, where -e is
the negative charge on the electron and E is the strength of the electric
field at that point in space. By the way, electric field is measured in
volts per meter, so if the plate voltage is, say 1000V, and the distance
between the plate and cathode is 1 cm = .01meter, then the average electric
field strength is 100,000 Volts/meter. That's actually quite a bit less than
the electric field you get when you walk across carpet in the dry winter and
touch something metal.
73,
Jim W8ZR

> -----Original Message-----
> From: Amps [mailto:amps-bounces at contesting.com] On Behalf Of Richard
Solomon
> Sent: Friday, December 02, 2016 08:22 PM
> To: amps at contesting.com
> Subject: Re: [Amps] Conventional" current flow
> 
> At the risk of "amplifying" the headache I already have over this
discussion ...
> 
> Who/What aims these little "things" so
> they hit the Plate/Anode ?
> 
> 73, Dick, w1KSZ
> 
> On Fri, Dec 2, 2016 at 8:00 PM, Jim Thomson <jim.thom at telus.net> wrote:
> 
> > Date: Fri, 2 Dec 2016 17:53:54 -0700
> > From: "Jim Garland" <4cx250b at miamioh.edu>
> > To: <amps at contesting.com>
> > Subject: Re: [Amps] "Conventional" current flow
> >
> > or that electrons in a vacuum tube are ejected from the cathode like
> > BBs and fly through the vacuum until they crash into the anode.
> >
> > 73,
> > Jim W8ZR
> >
> > ##  and here I thought all along that electrons crashed into the plate.
> >
> > Jim  VE7RF
> >
> >
> >
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