Cable Attenuation Question

Tue Sep 10 11:06:33 EDT 1996

In a message dated 96-09-09 23:47:50 EDT, you write:

>
>> This is a word Problem.
>> If I have a 150 Feet of RG-9913, which the charts say should have
>> a loss of 1.2 dB per 100 Feet at 28MHz. And I put 100 Watts of power
>> into the coax, how much power should I expect to see at the other end?
>> Thanks, Jack, KA8D
>----------------------
>Jack:
>
>

Hi Jack,

The overall attenuation is 1.8 dB, since it is 1.2 dB per 100 ft and you have
150 ft of cable (1.5 times 1.2 dB per 100= 1.8 dB)

The overall power loss at 28 MHz would be about 34 watts, you'd have about 66
watts left if SWR was 1:1 at the load.

73 Tom

>From hwardsil at wolfenet.com (Ward Silver)  Tue Sep 10 15:20:11 1996
From: hwardsil at wolfenet.com (Ward Silver) (Ward Silver)
Date: Tue, 10 Sep 1996 07:20:11 -0700 (PDT)
Subject: Cable Attenuation Question
Message-ID: <Pine.OSF.3.95.960910071355.17266A-100000 at gonzo.wolfenet.com>

> If I have a 150 Feet of RG-9913, which the charts say should have
> a loss of 1.2 dB per 100 Feet at 28MHz. And I put 100 Watts of power
> into the coax, how much power should I expect to see at the other end?
> Thanks, Jack, KA8D

1.2dB loss/100 ft x 150 ft = 1.8dB loss

         Pwr out				 	 -1.8
10 x log(-------) = -1.8  so  Pwr out = Pwr in (antilog (----)) 
         Pwr in						  10
				      = 100 (antilog (-0.18)

				      = 100 (0.661)

				      = 66.1W

73, Ward N0AX

>From hwardsil at wolfenet.com (Ward Silver)  Tue Sep 10 15:37:46 1996
From: hwardsil at wolfenet.com (Ward Silver) (Ward Silver)
Date: Tue, 10 Sep 1996 07:37:46 -0700 (PDT)
Subject: Cable Attenuation Question
Message-ID: <Pine.OSF.3.95.960910073605.17266G-100000 at gonzo.wolfenet.com>

On Mon, 9 Sep 1996, Jeff Singer wrote:
> 
> The answer is 75 watts (I'm not so smart; this from a little program on
> QRZ CD).
> 
> 73 de Jeff WA2SYN

BZZZZZT!  75 watts is what comes out the other end of 100-feet.  Jack has
150-feet for 1.8dB loss.

"I'll take coaxial attenuation for $300, please?"

73, Ward N0AX

>From n5ia at juno.com (Milt Jensen)  Tue Sep 10 15:39:32 1996
From: n5ia at juno.com (Milt Jensen) (Milt Jensen)
Date: Tue, 10 Sep 1996 10:39:32 EDT
Subject: To correct or not
References: <199609101350.IAA09773 at firefly.prairienet.org>
Message-ID: <19960910.143108.6974.0.N5IA at juno.com>

---Milt Jensen @ ARS N5IA---
---Virden, NM Route Box 176---
---Duncan, AZ -- 85534---
---H: (505) 358-2105      W: (520) 359-2503---
---Reply to n5ia at juno.com---

Comment regarding

On Tue, 10 Sep 1996 08:50:46 -0500 (CDT) w9sz at prairienet.org (Zack Widup)
writes:
>
>
>>
>>  Maybe we will have a race between KN5S and N4BO for this contest 
>(or
>>maybe KM5S will show up in a few logs)...
>>
>>Hey, don't forget about W6HB !!
>>Bobby
>>WB5B
>>
>
>The best one with my call so far: in the ARRL DX CW CONTEST a few 
>years 
>ago, someone logged me as W1ESZ    :-)
>
>Zack W9SZ

At times because of the way some operators scribble my call sign on their
notepads, I am responded to as a very exotic DX station
with the call sign of n51a (N  fifty one Alpha).  That is my only claim
to fame.
			73 de Milt, Number 5 Intelligent Amateur

>From seay at alaska.net (Del Seay)  Tue Sep 10 14:42:01 1996
From: seay at alaska.net (Del Seay) (Del Seay)
Date: Tue, 10 Sep 1996 06:42:01 -0700
Subject: Cable Attenuation Question
References: <199609101339.IAA08494 at firefly.prairienet.org>
Message-ID: <32357029.12D8 at alaska.net>

Zack Widup wrote:
> 
> >
> >> This is a word Problem.
> >> If I have a 150 Feet of RG-9913, which the charts say should have
> >> a loss of 1.2 dB per 100 Feet at 28MHz. And I put 100 Watts of power
> >> into the coax, how much power should I expect to see at the other end?
> >> Thanks, Jack, KA8D
> >----------------------
> >Jack:
> >
> >The answer is 75 watts (I'm not so smart; this from a little program on
> >QRZ CD).
> >
> >73 de Jeff WA2SYN
> >js at li.net
> 
> I get 66 watts out for 150 feet from my hand calculator. I get 75 watts
> out for 100 feet of coax.
> 
> Is this a new form of CONTEST?   :-)
> 
> Zack W9SZ
> 
> --

Great subject: Showed me my math gets worse as I get older.
I originally told Jack it was 52 watts - miscalculated!!
1.2 dB X 1.50 (150')= 1.8 dB loss.
1.8 dB = .6607, so obviously it would be 66 watts properly terminated
and no loss in connectors.
I had converted to dBm (50 dBm = 100 watts), subtracted 1.8dB and 
came up with 52 watts. Gawd I'm good!
73 de KL7HF

>From weinfurtner at ouvaxa.cats.ohiou.edu (Greg Weinfurtner)  Tue Sep 10 14:46:00 1996
From: weinfurtner at ouvaxa.cats.ohiou.edu (Greg Weinfurtner) (Greg Weinfurtner)
Date: Tue, 10 Sep 1996 10:46:00 -0300
Subject: Cable attenuation
Message-ID: <v03007802ae5b1e2ee04a@[132.235.72.11]>

Gang,
	This is a good problem!  Here is the formula for db

	db= 10 log (power IN/OUT Ratio)

A. His total loss in 150' is 1.8db  (That is 1.2db per 100 feet)

B.	-1.8db= 10 log (x/100)

C.	-.18db= log (x/100)

D.	10 ^ -.18= .661    (^ means exponential or "to the power of")

E.	100 * .661= 66.1 WATTS

F.	Plug it back into the formula and voila!, seems to check OK!

CU all this month in the contests!  73 de

****************************************************************************
*                                                Greg Weinfurtner AEE BSS  *
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*     N N   N   S         8     8   O     O      Ohio University   Athens  *
*    N  N  N   SSSSSSS   8888888   O     O       GO BOBCATS!               *
*   N   N N         S   8     8   O     O                                  *
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*              DXCC WAS EM89               thee, 'Here we are'? Job 38:35  *
*    weinfurtner at ouvaxa.cats.ohiou.edu                                     *
* http://ouvaxa.cats.ohiou.edu/~weinfurtner                                *
****************************************************************************

>From wa2syn at li.net (Jeff Singer)  Tue Sep 10 15:49:51 1996
From: wa2syn at li.net (Jeff Singer) (Jeff Singer)
Date: Tue, 10 Sep 1996 10:49:51 -0400 (EDT)
Subject: Cable Attenuation Question
Message-ID: <Pine.SUN.3.95.960910104451.12150D-100000 at linet01>

OK, Zack, and everyone else who brought the error to my attention: ur
absolutely right. Thought he was using 100' instead of 150. That's what I
get for reading my mail after 11pm (and I DID say I wasn't so smart)! 

73 de Jeff WA2SYN
js @li.net
------------------------------------------

On Tue, 10 Sep 1996, Zack Widup wrote:
>
>
> >> If I have a 150 Feet of RG-9913, which the charts say should have
> >> a loss of 1.2 dB per 100 Feet at 28MHz. And I put 100 Watts of power
> >> into the coax, how much power should I expect to see at the other end?
> >> Thanks, Jack, KA8D
> >----------------------
> >Jack:
> >
> >The answer is 75 watts (I'm not so smart; this from a little program on
> >QRZ CD).
> >
> >73 de Jeff WA2SYN
> >js at li.net 
> 
> I get 66 watts out for 150 feet from my hand calculator. I get 75 watts 
> out for 100 feet of coax.
> 
> Is this a new form of CONTEST?   :-)
> 
> Zack W9SZ
> 
> --
> 
> 