[CQ-Contest] For max total ponts go M/2 or two M/S?

[David Robbins K1TTT]

A big variable you didn't address... which contest?


David Robbins K1TTT
e-mail: mailto:k1ttt at arrl.net
web: http://www.k1ttt.net
AR-Cluster node: 145.69MHz or telnet://dxc.k1ttt.net
 

> -----Original Message-----
> From: cq-contest-bounces at contesting.com [mailto:cq-contest-
> bounces at contesting.com] On Behalf Of Jim Smith
> Sent: Saturday, January 12, 2008 02:00
> To: cq-contest reflector
> Subject: [CQ-Contest] For max total ponts go M/2 or two M/S?
> 
> If I want to maximize the total points made by a station with 2 op
> positions, there is a choice between M/2 or M/M or two M/s under
> separate calls.
> 
> We're going here for max total points generated by the two op positions
> for our own obscure reasons.  I do understand that one cannot combine
> the scores from 2 M/S entries for any known (other than Poisson d'Avril)
> awards.
> 
> So, let's compare 2 M/S stations to a M/2 just for fun.  This assumes
> that both stations work on all bands, that the rigs and antennas are
> identical, the ops all have comparable skills, band conditions are as we
> find them these days at the bottom of the cycle and that there are no
> band change rules.  If there are, well you just go M/M.
> 
> For a start, 2 M/S is clearly more fun as the ops can get in more op
> time.  But, remember that we're trying to maximize score here.
> 
> If the M/2 can make 3,000 Qs then the same number of ops split between 2
> M/S stations should easily be able to make more than 3,000 between them
> because they have different calls and are, therefore, fresh meat when
> they take over a band, particularly if they alternate on the good bands
> instead of one stn working out 20m while the other one twiddles its
> thumbs on 15 or 40. Let's say the 2 M/S's make a total of 3500 Qs (1750
> each).
> 
> I think a similar argument holds for mults.  If the M/2 can make 200
> mults then the same number of ops on 2 M/S stations should easily be
> able to make more than 200 between them.  Let's say they make a total of
> 300 (150 each).
> 
> Assuming that points = Qs times Mults
> 
> M/2 makes 3000 Qs times 200 mults = 600,000 points
> Each M/S makes 1750 Qs times 150  = 262,500 points
> So 2 M/S make                       525,000 points.
> 
> Well, the difference isn't as large as I expected.
> 
> If the M/S's each make 2,000 Qs then it's dead even.
> 
> Now, if the M/S's each make 2,000 Qs and 200 mults then they make
> 400,000 times 2 = 800,000 points.  But, to get the 200 mults they have
> to be really efficient at swapping bands and knocking off the mults.
> 
> If the M/S's can operate on the same band at the same time and not cause
> any problems at all for each other then maybe they could each get pretty
> well the same number of Qs and mults as the M/2 as they could both be on
> the high rate bands at the same time.  This gives a score of 1,200,000.
> 
> Hmm... I see many filters and miles of coax stubs in the future.
> 
> Anyway, these are pretty idealistic assumptions.
> 
> Which way do you think will maximize the total points?
> 
> 73, Jim	VE7FO
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