[CQ-Contest] Accuracy Top Ten Box

Steve Dyer w1srd at yahoo.com
Wed Apr 2 19:49:25 EDT 2014

So (1 + 1)/2 = 100%
Makes zero sense since this is really a statistical problem and a simple average is meaningless - unless of course you just want to make one perfect QSO!

 From: VE5ZX <ve5zx at hotmail.com>
To: cq-contest at contesting.com 
Sent: Wednesday, April 2, 2014 12:28 PM
Subject: Re: [CQ-Contest] Accuracy Top Ten Box

>An interesting idea.  What is the accepted definition for
> calculating "accuracy"?

(% correct calls + % correct exchanges)/2 ?

Syl -VE5ZX
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