[TenTec] Voltages on 50 ohm Dummy Load

[Ken Brown]

>I measure the peak to peak value using my scope.  Then power equals E 
>squared divided by R.  This is good enough for "government work".
>  
>
This is wrong! Using peak voltage instead of RMS voltage of the peaks 
will result in a power miscalculation by a factor of two. Using Peak to 
Peak voltage instead of RMS voltage of the peaks would result in a 
miscalculation by a factor of 8!

Peak voltage is 1.414 X RMS. Peak to peak voltage is 2 X Peak or 2 X 
1.414 X RMS. When you square this in the power equation your 
miscalculated power would be 8 X the actual power.

DE N6KB