Topband: Coax capacitor losses
Terry Conboy
n6ry at arrl.net
Thu Dec 23 13:54:34 EST 2004
At 05:29 AM 2004-12-22, Peter PA3AUC wrote:
>Now take as an example an open-ended, 10m long piece of RG-58 with an
>assumed
>attenuation of ~2 dB/100m at f = 1.8 MHz, and a velocity factor of 0.66.
>Inserting Zo = 50 ohm, ZL = 'infinite' , you'll find:
>Zi = 3.9 - j 77.7 ohms, which you can think of a 1.14 nF capacitor with
>a Q of ~20.
>Not very good, indeed! Note: I did the calculations using MathCad.
I wanted to see if I could reproduce this result with tools at my
disposal. I used TLW (version 1.0 from N6BV) and XLZIZL (from AC6LA) and
got a much lower series resistance. Both of these programs had a selection
for Belden 8259 (RG-58A). For a 10 meter stub at 1.8 MHz with a 10 Megohm
termination (they don't allow an open circuit), TLW gave Zi of 0.76 - j
77.77 ohms and XLZIZL gave 0.82 - j 77.75 ohms or a Q of about 95. Still a
poor Q for a capacitor. In a matched nominal 50-ohm circuit, this would be
about 0.07 dB loss (24 watts out of 1500).
>Putting two half-length coax stubs in parallel (5m each in this
>example) does *not*
>reduce the power loss as compared to the original full-length stub.
>You can easily do the math yourself ;-)
Doing the math myself (aided by XLZIZL), I used a 5.443 meter stub of
Belden 8259 (RG-58A), which gives Zi of 0.42 - j 155.5 ohms or a Q of about
370, a great improvement (but still a marginal capacitor Q). (A 5 meter
stub gives somewhat more than twice the reactance of a 10 meter stub, thus
the odd length.) It would seem that paralleling two of these stubs would
give Zi of 0.21 - j 77.75 ohms or about 1/4 the loss resistance of the
single 10 meter stub (under 0.02 dB or about 6.3 watts out of 1500).
Did I miss something?
73, Terry N6RY
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