Topband: How do you count the turns on a binocular core?

Kenneth Grimm kgrimm at adelphia.net
Thu Jan 11 23:06:04 EST 2007



Tom Rauch wrote:
>> John Devoldere, ON4UN, in his book, Low Band DXing, 4th 
>> ed. on page
>> 7-59, suggests that there would be one wire in each side 
>> of the
>> binocular core to have a two turn winding (4 passes, 2 
>> turns).
>>     
>
> In manufacturing and in my own Ham life a "turn" is a pass 
> through the core. In a binocular core a turn is *generally* 
> considered once through and once back, unless the two holes 
> are used independently instead of for a common winding.
>
> I started using the word "pass" with employees back in the 
> 80's when dealing with toroids, as a "pass" through the 
> hole. The reason for this is employees would often count the 
> wire outside the hole as a turn, but that wire has virtually 
> no effect at all on what goes on. It's only the pass through 
> the hole that matters.
>
> In an air-wound coil you do not count the start. It is the 
> zero turn. In a toroid the very first pass (or start) is a 
> turn. It is turn number one.
>
> 73 Tom 
>
>   
The problem, for me, is in the apparent inconsistency in the 4th edition 
of ON4UN's book on page 7-58 where he answers the question, "What is one 
turn?" and the diagram on the facing page (7-59) which shows something 
entirely different.  His answer is the same as you have indicated the 
*generally* accepted answer to be, that is, a loop going through both 
sides and back to the beginning = 1 turn.  However the diagram indicates 
that same loop to be 4 passes and 2 turns.  It seems that  as the wire 
passes through each opening (two openings on each side of the binocular 
core for a total of four openings) you get one pass.  One pass as the 
wire enters the first opening and a second as it exits the core, a third 
pass as you bend the wire and start back through the other side of the 
core and a fourth pass as it exits.  According to the diagram, these 
four passes constitute two turns.  Apparently, the diagram is wrong.
73,

-- 

Ken K4XL
k4xl at arrl.net

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