[TowerTalk] Fwd: Comment on twr derating

UpTheTower UpTheTower@aol.com
Fri, 16 Jan 1998 17:19:15 EST


This is a multi-part message in MIME format.

--part0_884989172_boundary
Content-ID: <0_884989172@inet_out.mail.aol.com.1>
Content-type: text/plain; charset=US-ASCII


--part0_884989172_boundary
Content-ID: <0_884989172@inet_out.mail.aol.com.2>
Content-type: message/rfc822
Content-transfer-encoding: 7bit
Content-disposition: inline

Return-Path: <hank.lonberg@harrisgrp.com>
Received: from  relay17.mail.aol.com (relay17.mail.aol.com [172.31.106.71]) by
	air28.mail.aol.com (v37.8) with SMTP; Fri, 16 Jan 1998 13:35:10 -0500
Received: from dayton.akorn.net (dayton.akorn.net [205.217.100.11])
	  by relay17.mail.aol.com (8.8.5/8.8.5/AOL-4.0.0)
	  with ESMTP id NAA10337 for <upthetower@aol.com>;
	  Fri, 16 Jan 1998 13:35:07 -0500 (EST)
Received: from deimos.spiretech.com (0@deimos.spiretech.com [207.173.200.226])
	by dayton.akorn.net (8.8.5/8.8.5) with ESMTP id NAA21019
	for <k7lxc@contesting.com>; Fri, 16 Jan 1998 13:35:04 -0500 (EST)
Received: from harrisgrp.com ([207.173.208.13] (may be forged))
	by deimos.spiretech.com (8.8.6/8.8.6) with ESMTP id LAA29593
	for <k7lxc@contesting.com>; Fri, 16 Jan 1998 11:26:51 -0800
Message-ID: <34BF389E.5475B9FD@harrisgrp.com>
Date: Fri, 16 Jan 1998 10:38:22 +0000
From: Hank Lonberg <hank.lonberg@harrisgrp.com>
X-Mailer: Mozilla 4.03 [en] (Win95; I)
To: k7lxc@contesting.com
Subject: Comment on twr derating
Content-type: text/plain; charset=US-ASCII
Content-transfer-encoding: 7bit

Steve:

I was browsing thru tower talk archives, I'm not subscribed and ran
across the attached message concerning derating a crank-up tower. To
properly derate the tower an engineer needs to look at this case.
Consider the following per the 1994 UBC

the basic stagnation wind pressure formula is   Q= 0.00256 * V*V
where Q is in psf and V is in mph.

This is the basic wind pressure that is modifiec for height, exposure,
gust, importance and
geometric coefficients.

Basically if increase from 50 mph to 80 mph then the increase is:

(80/50)(80/50) = 2.56  due to the fact that it is a function of the
velocity squared.

Hope this helps this gentleman and others.

KR7X / Hank Lonberg P.E. (structural engineer and ARRL VCE)



--part0_884989172_boundary--

--
FAQ on WWW:               http://www.contesting.com/towertalkfaq.html
Submissions:              towertalk@contesting.com
Administrative requests:  towertalk-REQUEST@contesting.com
Problems:                 owner-towertalk@contesting.com
Search:                   http://www.contesting.com/km9p/search