[TowerTalk] Ginpole for 20 foot sections

[Mark Brown]

when lifting a dead load with a single pulley you would have
the 500lbs of weight plus 500 pounds of downforce for a
total of 1000 lbs. With a 5:1 advantage you now have 500 lbs
of dead weight plus 100 lbs of downforce for a total of 600
lbs.


Ed Wolf wrote:
> 
> My turn...
> 
> Let me see if I now, after the past few days, understand.
> If I use a block and tackle with a 5:1 mechanical advantage
> attached to a beam in my garage to lift a 500 pound load,
> the 500 pound load will only weigh 100 pounds at the point
> of attachment on the beam? I like that idea! Seeing as how
> the beam in my garage will only support 125 pounds I can
> do just that according to all that I have read!
> 
> Ed Wolf - ars:N3UE - NA40+TR.PA
> http://members.home.net/wolfie132/
> http://www.breezeshooters.net
> http://www.breezeshooters.com
> 
> -----Original Message-----
> From: owner-towertalk@contesting.com
> [mailto:owner-towertalk@contesting.com]On Behalf Of David Robbins
> Sent: Wednesday, June 13, 2001 3:19 PM
> To: reflector -tower
> Subject: Re: [TowerTalk] Ginpole for 20 foot sections
> 
> >
> WRONG!  the higher the mechanical advantage of the block and tackle the
> lower
> the load on what is holding it up(diregarding the weight of the tackle
> itself).
> i'm sorry if you just don't get it, i've explained it as many different ways
> as
> i can.  maybe you should go see a mechanics professor at a local college or
> something and figure out how to balance the forces on the pole.
> 
> but what you really have to understand for the basic ham case with only a
> single
> pulley at the top of the gin pole is that the pole has to be able to hold
> more
> than twice the dead load you are lifting.
> 
> --
> David Robbins K1TTT
> e-mail: mailto://k1ttt@berkshire.net
> web: http://www.k1ttt.net
> AR-Cluster node: 145.69MHz or telnet://k1ttt.net
> 
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-- 
en24gp 6m through 1296, BBQ rules, icq 41823284

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