[TowerTalk] deep base for MA-550

Jerry Keller k3bz at arrl.net
Sat Oct 4 21:40:10 EDT 2003


There are 27 cu ft in 1 cu yd (3 ft x 3 ft x 3 ft)...so 2.5 ft x 2.5 ft x 5.0 ft = 31.25 cu ft... divided by 27 cu ft = 1.157 cu yd.  Jerry K3BZ
  ----- Original Message ----- 
  From: Jim Rhodes 
  To: gdaught6 at stanford.edu ; towertalk at contesting.com 
  Sent: Saturday, October 04, 2003 8:19 PM
  Subject: Re: [TowerTalk] deep base for MA-550


  Hold on here. Isn't the formula pi*r^2*h=v? My calc says about 78.5 cu ft 
  or 2.9 cu yds.

  Oh, I'm sorry. I just noticed the @stanford.edu.

  At 05:18 PM 10/4/03, gdaught6 at stanford.edu wrote:
  >On 4 Oct 2003 at 11:47, David Giuliani wrote:
  >
  > > I'm installing a concrete base for a Universal Towers MA-550.  The
  > > mfg's dwg calls for a base 2.5' x 2.5' x 5' deep in undisturbed soil,
  > > using 2.5 cubic yards.
  >
  >I calculate under 1.25 cubic yards for that hole.  You're going to
  >have a LOT of concrete left over.  3' x 3' x 6' is two yards.
  >
  >73,
  >
  >
  >
  >
  >_______________________________________________
  >
  >See: http://www.mscomputer.com  for "Self Supporting Towers", "Wireless 
  >Weather Stations", and lot's more.  Call Toll Free, 1-800-333-9041 with 
  >any questions and ask for Sherman, W2FLA.
  >
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  Jim Rhodes K0XU
  jim at rhodesend.net
  _______________________________________________

  See: http://www.mscomputer.com  for "Self Supporting Towers", "Wireless Weather Stations", and lot's more.  Call Toll Free, 1-800-333-9041 with any questions and ask for Sherman, W2FLA.

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