[TowerTalk] LAT/LONG QUESTION

Bob Nielsen nielsen at oz.net
Sat Apr 2 11:54:14 EST 2005


On Sat, Apr 02, 2005 at 11:38:10AM -0500, Gene WØQFC wrote:
> My logging program requires that I enter the lat & long figures as:
> 
> 28.xxxxxx and -82.xxxxxx.
> 
> I have the figures from my GPS receiver but they are expressed as:
> 
>    28.27.319 N
> _82.36.623.W
> 
> How do I convert the above to the 28.xxxxxx format?
> Thanks in advance.
> 
> Gene, WØQFC
> Spring Hill, FL
> 

I suspect that what it means is 28 deg, 27.319 min N and 82 deg, 36.623 
min W.  Since there are 60 minutes in a degree, that becomes:  

28 + 27.319/60 deg = 28.45531667 deg  and
82 + 36.623/60 deg = 36.61038333 deg

73,
Bob, N7XY


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