[TowerTalk] Max Unguyed Rohn 25 height to support dipole end

[D. Scott MacKenzie]

OK - I was assuming that the dipole was going to be at the center and draped
inverted V style. I didn't think about using multiple towers - guess that is
what happens when I assume.  When set up as an inverted V, it would not be
as bad, since the forces would be roughly equal and opposite.

Using two towers with the dipole between them, and the dipole on a
centenary, then the forces are offset - and they would be at the max rated
load - no disagreement there.

Regardless of the height - it will still be less that 40 feet in the
air.....kind of pointless as everything will go straight up in the air and
warm the clouds....

Scott

-----Original Message-----
From: towertalk-bounces at contesting.com
[mailto:towertalk-bounces at contesting.com]On Behalf Of Jim Lux
Sent: Saturday, November 11, 2006 7:37 PM
To: kb0fhp at comcast.net; kdm at ctcn.net; TowerTalk at contesting.com
Subject: Re: [TowerTalk] Max Unguyed Rohn 25 height to support dipole
end


At 03:59 PM 11/11/2006, D. Scott MacKenzie wrote:
> >From the 2004 Rohn Catalog, p 116, at 70 mph, the maximum freestanding
>height is 40 feet - with a 1.5 ft^2 loading - no ice.
>
>Scott


1.5 sq ft @ 70 mi/hr is 19 pounds..

If tension is 40 odd pounds (see previous mail with catenary
calculation), you're probably a bit overloaded...




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