[TowerTalk] Connector Loss Question

[Steve Hunt]

Joe,

Sorry to "nit pick", but if your formula is correct and the constant is 
0.5, shouldn't the loss be 0.57dB? It makes a big difference if you have 
several connectors in the chain.

73,
Steve G3TXQ


Joe Reisert, W1JR wrote:
> Hi Manius,
>
> The insertion loss of a good N connector is equal to the square root 
> of F (in GHz) times a constant (K).
>
> The constant for a single N connector is 0.5. Therefore, at 23 CM 
> (1.3 GHz) the loss is approximately .057 dB so you can add up the 
> losses based on your situation.
>
> 73,
>
> Joe, W1JR
>
>   
>