Rich Measures wrote:
>>
>P=I^2*R. P=10a^2*1 ohms =100*1 =100W Is this the rating of the resistor
>in question, Ian?
I beg your pardon: make that 3-and-a-bit amps continuously, for a 1-ohm,
10W resistor. Therefore whatever current burned that resistor out was
>3A for several minutes probably, or >>3A for a much shorter time.
The same conclusion still applies, though. It seems incredible that so
much grid current could be flowing in an oscillation condition. I mean,
if that was the grid current, how big would the cathode current have to
be... and where would it come from?
73 from Ian G3SEK Editor, 'The VHF/UHF DX Book'
'In Practice' columnist for RadCom (RSGB)
http://www.ifwtech.demon.co.uk/g3sek
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