>
>Maybe I take too simplistic a view. I figure as follows:-
>
>When the tube is drawing the peak plate current (i.e. at the peak of the rf
>cycle), the plate voltage should be at its minimum value. So the load
>resistance that the plate needs to see is the (HV supply minus the minimum
>plate voltage) divided by the peak plate current.
>
? Indeed, and the result seems to work well enough.
- cheers, Peter.
Rich...
R. L. Measures, 805-386-3734, AG6K, www.vcnet.com/measures
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