In a PI-L output network, is the RF current the same or different in the PI
inductor (L1) and the L inductor (L2) ?
On the one hand, it would seem that the currents would be the same since
the inductors are in series. However on the other hand, since the network is a
stepdown impedance transformer, it would seem that the current in L2 would be
greater than in L1 due to the transformer action.
In most of the amp designs that I have seen, the 10 meter portion of L1
typically is 1/4" tubing and the 10 meter portion of L2 is #12 gauge wire.
If the current is the same or greater in L2, why shouldn't the conductor
of L2 be at least as large or larger than that of L1 ?
Thanks to anyone who can clear this up for me.
73 Don K9MUF
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