On Tue, 9 Feb 1999 15:35:42 -0600 "Roy Koeppe" <email@example.com> writes:
>L1 has much greater, internal circulating currents than L2 has. With
>loaded Q's, L1 could easily have ten times the current of L2.
Not likely. If the 50 Ohm current is 5-6A then there would not be any ham
amps produced that would survive with 50-60A in L1. I would guess 2-3
times would be more in line with a good design.
In my experience with PI-L's it is a voltage breakdown and not current
heating that destroys many bandswitches.
73 Carl KM1H
>From: JWebs3939@aol.com <JWebs3939@aol.com>
>To: firstname.lastname@example.org <email@example.com>
>Date: Tuesday, February 09, 1999 3:14 PM
>Subject: [AMPS] PI-L network inductor wire sizes
>> In a PI-L output network, is the RF current the same or different
>>inductor (L1) and the L inductor (L2) ?
>> On the one hand, it would seem that the currents would be the
>>the inductors are in series. However on the other hand, since the
>>stepdown impedance transformer, it would seem that the current in L2
>>greater than in L1 due to the transformer action.
>> In most of the amp designs that I have seen, the 10 meter portion
>>typically is 1/4" tubing and the 10 meter portion of L2 is #12 gauge
>> If the current is the same or greater in L2, why shouldn't the
>>of L2 be at least as large or larger than that of L1 ?
>> Thanks to anyone who can clear this up for me.
>> 73 Don K9MUF
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