So, I am using an oscilloscope with an RF sampler to measure output power.
With barefoot 100 watts, I read 0.6 volts p-p on the scope.
With the amp in line, I read 2.0 volts p-p on the scope.
What is my output power?
20 log (2.0/0.6) = 10.46 dB
I divide 10.46 dB by 10 and get 1.46 dB.
I take 10 to the 1.46 power and get 11.11.
I multiply by 100 and get 1111 watts output.
Is that correct?
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